Und die Zeile 68 ist
echo $backid;
echo $backid;
"Zeile der Notice" sagt mir nichts.
Undefined variable: backid in ... on line 68"
Und die Zeile 68 ist
$backquery = "SELECT id FROM images WHERE datetime < ? ORDER BY datetime DESC LIMIT 1";
$backstmt = mysqli_stmt_init($verbindung);
if (mysqli_stmt_prepare($backstmt, $backquery)) :
if (!$backstmt) :
die('mysqli error: '.mysqli_error($verbindung));
endif;
if (!mysqli_stmt_bind_param($backstmt, "i", $thisdatetime)) :
die('mysqli error: '.mysqli_error($verbindung));
endif;
if (!mysqli_stmt_execute($backstmt)) :
die('mysqli error: '.mysqli_error($verbindung));
endif;
if (!mysqli_stmt_bind_result($backstmt, $backid)) :
die('mysqli error: '.mysqli_error($verbindung));
endif;
if (!mysqli_stmt_fetch($backstmt)) :
die('mysqli error: '.mysqli_error($verbindung));
endif;
endif;
$driver = new mysqli_driver();
$driver->report_mode = MYSQLI_REPORT_ERROR|MYSQLI_REPORT_STRICT;
$backquery = "SELECT id FROM images WHERE datetime < ? ORDER BY datetime DESC LIMIT 1";
$backstmt = mysqli_stmt_init($verbindung);
mysqli_stmt_prepare($backstmt, $backquery);
mysqli_stmt_bind_param($backstmt, "i", $thisdatetime);
mysqli_stmt_execute($backstmt);
mysqli_stmt_bind_result($backstmt, $backid);
mysqli_stmt_fetch($backstmt);
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