Hey kann mir wer helfen ich finde in meinen Code den Fehler nicht.
Der zeigt son Fehler an:
Danke schon mal für eure Hilfe
PHP-Code:
<?php
if (button==" OK ") {
include("db.php");
$query = "SELECT * FROM login WHERE id='$id'";
$result = mysql_query($query);
$line = mysql_fetch_array($result)
?>
<?php
$id3 = $line[id];
setcookie ("id3",$id3, time()+3600);
$Angriff5 = $line[Angriff];
setcookie ("Angriff5",$Angriff5, time()+3600);
$v6 = rand(1,3);
if ($Angriff5>=4) {
$v6 = rand(2,5);
}
include("db.php");
$query = "SELECT * FROM login WHERE user='$user6'";
$result = mysql_query($query);
$line = mysql_fetch_array($result)
if ( $line[user] != $user6 ) {
echo "Dieser User existiert nicht!"
} else {
$id4 = $line[id];
setcookie ("id4",$id4, time()+3600);
$Angriff6 = $line[Angriff];
setcookie ("Angriff6",$Angriff6, time()+3600);
$v7 = rand(1,3);
if ($Angriff6>=4) {
$v7 = rand(2,5);
}
if ($v6>$v7) {
echo "Du hast gewonnen!";
include("db.php");
$query = "SELECT * FROM login WHERE id='$id4'";
$result = mysql_query($query);
$line = mysql_fetch_array($result)
$Geld8 = $line[Geld] ;
$Geld9 = 0;
include("db.php");
mysql_query("UPDATE login SET Geld='$Geld9' WHERE id='$id4'");
mysql_close();
include("db.php");
$query = "SELECT * FROM login WHERE id='$id3'";
$result = mysql_query($query);
$line = mysql_fetch_array($result)
$Geld10 = $Geld8 + $line[Geld] ;
include("db.php");
mysql_query("UPDATE login SET Geld='$Geld10' WHERE id='$id3'");
mysql_close();
?>
<?php
}
if ($v7>$v6) {
echo "Du hast verloren!";
include("db.php");
$query = "SELECT * FROM login WHERE id='$id3'";
$result = mysql_query($query);
$line = mysql_fetch_array($result)
$Geld8 = $line[Geld] ;
$Geld9 = 0;
include("db.php");
mysql_query("UPDATE login SET Geld='$Geld9' WHERE id='$id3'");
mysql_close();
include("db.php");
$query = "SELECT * FROM login WHERE id='$id4'";
$result = mysql_query($query);
$line = mysql_fetch_array($result)
$Geld10 = $Geld8 + $line[Geld] ;
include("db.php");
mysql_query("UPDATE login SET Geld='$Geld10' WHERE id='$id4'");
mysql_close();
?>
<?php
}
if ($v7==$v6)
echo "Unentschieden!";
}
}
?>
<br />
<a href="hs.php?id=<?PHP echo $id3; ?>"><strong><span class="Stil1">Zum Hauptmenü</span></strong></a>
<?php
}
?>
<form method="post" action="Angriff.php?id=<?PHP echo $id; ?>?user=<?PHP echo $user6; ?>">
<input type="text" name="user6" value=""><br>
<input type="submit" name="button" value=" OK ">
</form>
PHP-Code:
Parse error: syntax error, unexpected T_IF in /usr/export/www/vhosts/funnetwork/hosting/fightgame/Attacke.php on line 34
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